Conditional Probability – Solved Problems

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Conditional Probability – Solved Problems with Step-by-Step Solutions

Conditional Probability – Solved Problems

Conditional probability deals with finding the probability of an event when another related event has already occurred. It is a crucial topic in statistics, data science, competitive exams, and real-life decision-making.

P(A | B) = P(A ∩ B) / P(B)
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Problem 1: Basic Conditional Probability

A card is drawn from a standard deck of 52 cards. Find the probability that the card is an Ace, given that it is a red card.

Solution:

Red cards = 26 Red Aces = 2

P(Ace | Red) = 2 / 26 = 1 / 13

Answer: Probability = 1/13

Problem 2: Dice-Based Conditional Probability

Two dice are thrown. Find the probability that the sum is 10, given that the first die shows a 4.

Solution:

If the first die is 4, possible outcomes are: (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

Sum = 10 occurs when (4,6)

P = 1 / 6

Answer: Probability = 1/6

Problem 3: Students Passing Exams

In a class, 60% students pass Mathematics, 50% pass Science, and 30% pass both. Find the probability that a student passes Mathematics given that the student passed Science.

Solution:

P(M | S) = P(M ∩ S) / P(S)

P(M | S) = 0.30 / 0.50 = 0.6

Answer: Probability = 0.6

Problem 4: Drawing Balls from a Bag

A bag contains 5 red and 7 blue balls. One ball is drawn at random. Find the probability that it is blue, given that it is not red.

Solution:

Not red = blue only Total blue balls = 7

P(Blue | Not Red) = 7 / 7 = 1

Answer: Probability = 1

Problem 5: Selecting a Student

Among 40 students, 25 play cricket, 20 play football, and 10 play both. Find the probability that a randomly selected student plays cricket, given that the student plays football.

Solution:

P(C | F) = P(C ∩ F) / P(F)

P(C | F) = 10 / 20 = 1 / 2

Answer: Probability = 1/2

Problem 6: Defective Items

A box contains 12 bulbs, out of which 3 are defective. One bulb is selected at random. Find the probability that it is defective, given that it is not good.

Solution:

Not good bulbs = defective bulbs = 3

P(Defective | Not Good) = 3 / 3 = 1

Answer: Probability = 1

Problem 7: Real-Life Selection Problem

In a group of 100 people, 60 drink tea, 40 drink coffee, and 20 drink both. If a person is selected at random and is known to drink tea, find the probability that the person also drinks coffee.

Solution:

P(Coffee | Tea) = P(Tea ∩ Coffee) / P(Tea)

P = 20 / 60 = 1 / 3

Answer: Probability = 1/3

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Conclusion: Conditional probability helps in understanding dependent events and real-world uncertainty. It forms the foundation for Bayes’ theorem, statistics, and data-driven decision-making.

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