Compound Interest – Solved Problems

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Compound Interest Solved Problems | Step-by-Step Explanation

Compound Interest – Solved Problems with Explanation

Compound Interest is an important concept in finance and competitive mathematics. Unlike Simple Interest, interest is calculated on both the principal and the accumulated interest from previous periods.

This article provides multiple solved problems on Compound Interest with detailed, step-by-step explanations to help students master the topic.

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Compound Interest Formula

Amount (A) = P × (1 + R/100)T

Compound Interest (CI) = Amount − Principal

  • P = Principal
  • R = Rate of interest per annum
  • T = Time in years

Solved Compound Interest Problems

Problem 1: Find the compound interest on ₹10,000 at 10% per annum for 2 years.

Solution:

P = ₹10,000, R = 10%, T = 2 years

A = 10000 × (1 + 10/100)² = 10000 × (1.1)² = 10000 × 1.21 = ₹12,100

CI = A − P = 12,100 − 10,000 = ₹2,100

Compound Interest = ₹2,100

Problem 2: Find the amount after 3 years if ₹8,000 is compounded annually at 5%.

Solution:

A = 8000 × (1.05)³ = 8000 × 1.1576 = ₹9,261 (approx.)

Amount ≈ ₹9,261

Problem 3: Calculate the CI on ₹5,000 for 2 years at 8% per annum.

Solution:

A = 5000 × (1.08)² = 5000 × 1.1664 = ₹5,832

CI = 5832 − 5000 = ₹832

Compound Interest = ₹832

Problem 4: Find the principal if the amount becomes ₹13,310 in 3 years at 10% CI.

Solution:

A = ₹13,310, R = 10%, T = 3

P = A ÷ (1.1)³ = 13310 ÷ 1.331 = ₹10,000

Principal = ₹10,000

Problem 5: Find the CI on ₹16,000 at 10% per annum compounded half-yearly for 1 year.

Solution:

Rate per half-year = 10% ÷ 2 = 5% Time = 2 half-years

A = 16000 × (1.05)² = 16000 × 1.1025 = ₹17,640

CI = 17,640 − 16,000 = ₹1,640

Compound Interest = ₹1,640

Problem 6: Find the difference between CI and SI on ₹20,000 at 10% for 2 years.

Solution:

SI = (20000 × 10 × 2) ÷ 100 = ₹4,000

CI = 20000 × (1.1)² − 20000 = 24200 − 20000 = ₹4,200

Difference = 4,200 − 4,000 = ₹200

Difference = ₹200

Problem 7: At what rate will ₹4,000 become ₹4,840 in 2 years (CI)?

Solution:

A/P = 4840 ÷ 4000 = 1.21

(1 + R/100)² = 1.21 1 + R/100 = 1.1 R = 10%

Rate = 10% per annum

Problem 8: Find the CI earned if ₹6,250 becomes ₹7,562.50 in 2 years.

Solution:

CI = Amount − Principal = 7,562.50 − 6,250 = ₹1,312.50

Compound Interest = ₹1,312.50

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Exam Tips

✔ Always identify compounding period
✔ Convert rate and time accordingly
✔ Use (1 + R/100)² shortcut for 2 years

Common Mistakes

  • Forgetting to adjust rate for half-yearly compounding
  • Mixing SI and CI formulas
  • Calculation errors with powers
  • Incorrect difference calculation

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